Sunday, March 21, 2010
Genetic Problems
Okay... so I have slowly been plugging away at these questions. I've looked at the questions and answers, (or hints), that others have posted which has actually helped me a lot. However, one I cannot seem to fiure out is number 6. I'm pretty sure I am over thinking it, but I also could be going about it completly wrong! I get frustrated with so many componets and my thinking shuts down. So if anyone has any helpful hints concerning problem number 6 I would greatly appreciate it! Thank you very much ahead of time!
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Ok so I think I have it.
ReplyDeleteA and B: So each of the parents can only make 1 gametes. This is because they both only have one type of each traits. So the Male could only produce BR because it has BBRR. The Female could only make br because it only has bbrr. Since they only have 1 type of each of the traits, they can't make another type.
C and D: So when the F1 offspring are produced from the above parents one of the types of kids you can get is BbRr. Each of the parents can produce 4 gametes. These are BR, Br, bR, and br.
E: Because each of the parents can produce these 4 gametes, you need 16 boxes in your punnet square. 4 across and 4 down. Both sides are the same. BR, Br, bR, and br. Then you treat the punnet square like you would any other punnet square.
F: So the boxes in the punnet square (if you ordered them in the same order that I did in part E) should read
Row 1 from left to right: BBRR, BBRr, BbRR, BbRr
Row 2 from left to right: BBRr, BBrr, BbRr, Bbrr
Row 3 from left to right: BbRR, BbRr, bbRR, bbRr
Row 4 from left to right: BbRr, Bbrr, bbRr, bbrr
G: So the phenotype ratio is 1/16 BBRR, 2/16 BBRr, 2/16 BbRR, 4/16 BbRr, 2/16 Bbrr, 2/16 bbRr, 1/16 BBrr, 1/16 bbRR, and 1/16 bbrr. This is just counting the squares.
Sorry, for part C and D I wasn't really clear. When I said "Each of the parents" I was referring to if 2 BbRr were the parents. Not the BBRR and bbrr.
ReplyDeleteWow, that was very helpful to me. Thanks a lot!
ReplyDelete